Q. The magnetic moment of a transition metal is found to be $3.87\, BM$. Then the number of unpaired electrons present in the metal is :

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A

1

B

2

C

3

D

4

Solution:

Magnetic moment $\sqrt{n} \times(n+2)=\sqrt{4}(4+2)$
$=\sqrt{32}$
$=3.87$

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