An organic compound contains 78 % (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1]

Question

An organic compound contains 78 % (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1] (A) CH (B) CH 2 (C) CH 3 (D) CH 4

Tardigrade Admin · Accepted Answer

% C =78 % H =22 C: H =(78/12): (22/1) =6.5: 22 (6.5/6.5): (22/6.5)=1: 3.3 C: H = CH 3

Q. An organic compound contains $78%$ (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of $C$ is $12, H$ is $1$ ]

$C H$

$C H_{2}$

$C H_{3}$

$C H_{4}$

$% C = 78$
$% H = 22$
$C : H = \frac{78}{12} : \frac{22}{1}$
$= 6.5 : 22$
$\frac{6.5}{6.5} : \frac{22}{6.5} = 1 : 3.3$
$C : H = C H_{3}$

Q. An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12,H is 1]

CH

CH2​

CH3​

CH4​