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  3. Chemistry
  4. The magnetic moment of a transition metal is found to be 3.87 BM. Then the number of unpaired electrons present in the metal is :

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Q. The magnetic moment of a transition metal is found to be $3.87\, BM$. Then the number of unpaired electrons present in the metal is :

KCETKCET 2022

Solution:

Magnetic moment $\sqrt{n} \times(n+2)=\sqrt{4}(4+2)$
$=\sqrt{32}$
$=3.87$