Following limiting molar conductivities are given as λom(H2SO4) = x S cm2 mol-1 λom(K2SO4) = y S cm2 mol-1 λom(CH3COOK) =z S cm2 mol-1 λom(in S cm2 mol-1) for CH3COOH will be-

Question

Following limiting molar conductivities are given as λom(H2SO4) = x S cm2 mol-1 λom(K2SO4) = y S cm2 mol-1 λom(CH3COOK) =z S cm2 mol-1 λom(in S cm2 mol-1) for CH3COOH will be- (A) x - y + 2 z (B) x + y - z (C) x - y + z (D) ((x -y)/2)+z

Tardigrade Admin · Accepted Answer

CH3COOH arrow CH3COO- + H+ ...(1) H2SO4 arrow 2H+ + SO4-2 ...(2) K2SO4 arrow 2K+ + SO4-2 ...(3) CH3COOK arrow CH3COO- + K+ ...(4) According to Kohlrausch's law- λ°CH3COOH = λ°CH3COO- + λ°H+ eq.(1) = eq .(4) + eq . ((2)/2) - eq. ((3)/2) ∴ λ°CH3COOH = z + (X/2) - (Y/2) λ°CH3COOH = ((X - Y)/2) + z (S × cm2 mol-1)

Q. Following limiting molar conductivities are given as
$λ_{m}^{o} (H_{2} S O_{4}) = x S c m^{2} m o l^{- 1}$
$λ_{m}^{o} (K_{2} S O_{4}) = y S c m^{2} m o l^{- 1}$
$λ_{m}^{o} (C H_{3} COO K) = z S c m^{2} m o l^{- 1}$
$λ_{m}^{o} (in S c m^{2} m o l^{- 1})$ for $C H_{3} COO H$ will be-

$x - y + 2 z$

$x + y - z$

$x - y + z$

$\frac{( x - y )}{2} + z$

Q. Following limiting molar conductivities are given as λmo​(H2​SO4​)=xScm2mol−1 λmo​(K2​SO4​)=yScm2mol−1 λmo​(CH3​COOK)=zScm2mol−1 λmo​(inScm2mol−1) for CH3​COOH will be-

x−y+2z

x+y−z

x−y+z

2(x−y)​+z

Q. Following limiting molar conductivities are given as
$λ_{m}^{o} (H_{2} S O_{4}) = x S c m^{2} m o l^{- 1}$
$λ_{m}^{o} (K_{2} S O_{4}) = y S c m^{2} m o l^{- 1}$
$λ_{m}^{o} (C H_{3} COO K) = z S c m^{2} m o l^{- 1}$
$λ_{m}^{o} (in S c m^{2} m o l^{- 1})$ for $C H_{3} COO H$ will be-

$x - y + 2 z$

$x + y - z$

$x - y + z$

$\frac{( x - y )}{2} + z$