Q. Heisenberg uncertainity principle mathematically is

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$\Delta x=\frac{h}{4 \pi}$

$\Delta x \cdot \Delta p=\frac{h}{4 \pi}$

$\Delta x \cdot \Delta p \geqslant \frac{h}{4 \pi}$

$\Delta x=\Delta p$

Solution:

Correct answer is (c) $\Delta x \cdot \Delta p \geqslant \frac{h}{4 \pi}$

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