1. Tardigrade
  2. Question
  3. Mathematics
  4. Straight lines x - y = 7 and x + 4y = 2 intersect at B. Points A and C are so chosen on these two lines such that AB = AC. The equation of line AC passing through (2, -7) is

Q. Straight lines x - y = 7 and x + 4y = 2 intersect at B. Points A and C are so chosen on these two lines such that AB = AC. The equation of line AC passing through (2, -7) is

WBJEEWBJEE 2019 Report Error

Solution:

Let the slope of line AC be m,
then, AB = AC $\quad\quad\Rightarrow ∠ABC = ∠BCA$
$\therefore \left|\frac{m+\frac{1}{4}}{1-\frac{3}{4}}\right| = \left|\frac{-\frac{1}{4}-1}{1-\frac{1}{4}}\right|\quad\Rightarrow m = \frac{-23}{7}, 1$
$\therefore $ Equation of line is: $23x + 7y + 3 = 0, x - y = 9$

Solution Image

Questions from WBJEE 2019

1. T$\displaystyle\lim_{x \to 0+}$ $\left(x^{n} \,ln\, x\right), n > 0$

2. If $\int\,cos\,x\,log\left(tan \frac{x}{2}\right)dx = sin\,x\,log\left(tan \frac{x}{2}\right)+$ f(x) then f(x) is equal to, (assuming c is a arbitrary real constant)

3. $y = \int cos \left\{2tan^{-1} \sqrt{\frac{1-x}{1+x}}\right\} dx$ is an equation of a family of

4. The value of the integration $\int\limits^{ \pi/4}_{- \pi/4}$$\left(\lambda \left|sin\,x\right|+\frac{\mu\, sin \,x}{1+cos\,x}+\gamma\right)dx$

5. $\lim _{x \rightarrow 0} \frac{1}{x}\left[\int_{y}^{a} e^{\sin ^{2} t} d t-\int_{x+y}^{a} e^{\sin ^{2} t} d t\right]$ is equal to

Mathematics Most Viewed Questions

1. The solution of $\frac{dy}{dx} = \frac{y}{x}+\tan \frac{y}{x}$ is

WBJEE 2011 Differential Equations

2. The solution of the differential equation $\frac{dy}{dx} = (x +y)^2$ is

COMEDK 2009 Differential Equations

3. $\int\frac{1}{\sin x\, \cos x}$ dx is equal to

KEAM 2016 Integrals

4. If $\begin{bmatrix}1&- \tan\theta \\ \tan \theta&1\end{bmatrix}\begin{bmatrix}1&\tan \theta \\ - \tan \theta &1\end{bmatrix}^{-1} = \begin{bmatrix}a&-b\\ b&a\end{bmatrix}$ then

COMEDK 2009 Matrices

5. The value of $ \int{\frac{{{x}^{2}}+1}{{{x}^{4}}-{{x}^{2}}+1}}dx $ is

KEAM 2007 Integrals

Latest Updates