Question

${\lim }_{x\to 0}\frac{1}{x}\left[{\int }_y^a{e}^{{\sin }^{2}t}dt-{\int }_{x+y}^a{e}^{{\sin }^{2}t}dt\right]$ is equal to

• A. $e^{si{n}^{2}y}$
• B. $e^{2siny}$
• C. $e^{|siny|}$
• D. $e^{cose{c}^{2}y}$

Answer 1

Answer: (A)

$e^{si{n}^{2}y}$