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  4. Degree of the differential equation: [ 1 + 2 ((dy/dx))2]3/2 = 5(d2y/dx3) is

Q. Degree of the differential equation:
$\left[ 1 + 2 \left(\frac{dy}{dx}\right)^2\right]^{3/2} = 5\frac{d^2y}{dx^3}$ is

KCETKCET 2022 Report Error

Solution:

$f(1) = 1 $
$ L.L = \underset{x \rightarrow 1}{lt} (1-x) = 0 : R.L. \underset{x \rightarrow 1}{lt} (1 +x) = 2$
$L. L \ne R.L$
$\therefore \underset{x \rightarrow 1}{lt} f(x) $ does not exist

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