Question

Degree of the differential equation:
$\left[ 1 + 2 \left(\frac{dy}{dx}\right)^2\right]^{3/2} = 5\frac{d^2y}{dx^3}$ is

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (C)

$f(1) = 1 $
$ L.L = \underset{x \rightarrow 1}{lt} (1-x) = 0 : R.L. \underset{x \rightarrow 1}{lt} (1 +x) = 2$
$L. L \ne R.L$
$\therefore \underset{x \rightarrow 1}{lt} f(x) $ does not exist