Q. If A=[1−122311−23] then adj(A−1)=
Solution:
adj(A−1)=(adjA)−1=A|A| Now,
|A|=1.(9+2)+1⋅(6−1)+2⋅(−4−3)
=11+5−14=2
\therefore(\text{adj} A)^{-1}=\frac{1}{2} A
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