Q. What is the osmotic pressure of $3.42\%\left[\right.w/v\left]\right.$ sucrose solution $\left[\right.molwt=342\left]\right.$ at $127^\circ C?$
$R = 0 . 08 Latm$ $mol^{- 1}K^{- 1}\left.$

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$4atm.$

$3.2atm.$

$5atm$

$2.45atm$

Solution:

$\pi =iCRT=1\times \frac{3 . 42 \times 1000}{342 \times 100}\times 0.0821\times 400$
$=3.2atm$

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