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Tardigrade
Question
Chemistry
Volume of 0.1 textM textH2 textS textO4 required to neutralize 30 textm textL of 0.2 textN textN texta textO textH is
Q. Volume of
0.1
M
H
2
S
O
4
required to neutralize
30
m
L
of
0.2
N
N
a
O
H
is
1107
147
NTA Abhyas
NTA Abhyas 2020
Redox Reactions
Report Error
A
30
m
L
27%
B
15
m
L
31%
C
40
m
L
10%
D
60
m
L
33%
Solution:
0.1
M
o
f
H
2
S
O
4
⇒
0.2
N
o
f
H
2
S
O
4
∴
N
1
V
1
=
N
2
V
2
[
N
1
=
0.2
N
H
2
SO
4
]
0.2
×
V
1
=
30
×
0.2
∴
V
1
=
30
m
L