Q. What is the mass of oxalic acid required to prepare $500\, cm ^{3}$ of $0.2\, M$ solution

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9 g

1.26 g

6.3 g

12.6 g

Solution:

Mass required to prepare $1\, dm 3$ of $0.2\, M$ oxalic acid = molarity $\times$ mol. mass $=0.2 \times 126=25.2\, g$
$\therefore$ mass $/ 500\, ml =12.6\, g$

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