Q. The reaction condition leading to the best yield of $C_{2}H_{5}Cl$ are:

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A

$C_{2} H_{6} \left(\right. excess \left.\right) + C l_{2} \, \, \overset{U V \, \, l i g h t}{→}$

B

$C_{2} H_{6} + C l_{2} \left(\right. excess \left.\right) →_{r o o m \, \, t e m p .}^{d a r k}$

C

$C_{2} H_{6} + C l_{2} \, \, \overset{U V \, \, l i g h t}{→}$

D

$C_{2} H_{6} + C l_{2} \left(\right. excess \left.\right) \, \, \overset{U V \, \, l i g h t}{ \rightarrow }$

Solution:

During chlorination of alkane, if excess of an alkane is treated with $\left(Cl\right)_{2} \left(\right. g \left.\right)$ in presence of light or heat, the chance of mono–chlorination predominate.
$C_{2} H_{6} \left(\right. excess \left.\right) + C l_{2} \, \, \overset{U V \, \, l i g h t}{ \rightarrow } \left(CH\right)_{3} \, C H_{2} \, C l \, + H C l$

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