1. Tardigrade
  2. Question
  3. Chemistry
  4. The order of stability of the alkenes textR2 textC= textCR2 text, textR2 textC= textCHR text, textR2 textC= textCH2 text, textRCH= textCHR text, textRCH= textCH2 textI textII textIII textIV textV ( textR = - textCH text3 )

Q. The order of stability of the alkenes
$\text{R}_{2}\text{C}=\text{CR}_{2}\text{,} & \text{R}_{2}\text{C}=\text{CHR}\text{,} & \text{R}_{2}\text{C}=\text{CH}_{2}\text{,} & \text{RCH}=\text{CHR}\text{,} & \text{RCH}=\text{CH}_{2} \\ \text{I} & \text{II} & \text{III} & \text{IV} & \text{V}$
( $\text{R} = \, - \text{CH}_{\text{3}}$ )

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Solution:

More substituted alkenes are more stable (more hypercnjugation) and alkyl groups on two different carbon atoms makes it more stable
I > II > III > IV > V

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