Question

The order of stability of the alkenes
$\text{R}_{2}\text{C}=\text{CR}_{2}\text{,} & \text{R}_{2}\text{C}=\text{CHR}\text{,} & \text{R}_{2}\text{C}=\text{CH}_{2}\text{,} & \text{RCH}=\text{CHR}\text{,} & \text{RCH}=\text{CH}_{2} \\ \text{I} & \text{II} & \text{III} & \text{IV} & \text{V}$
( $\text{R} = \, - \text{CH}_{\text{3}}$ )

• A. I > II > III > IV > V
• B. I = II > III > IV > V
• C. II > I > IV > III > V
• D. V > IV > III > II > I

Answer 1

Answer: (A)

More substituted alkenes are more stable (more hypercnjugation) and alkyl groups on two different carbon atoms makes it more stable
I > II > III > IV > V