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  4. The maximum number of possible interference maxima for slit separation equal to 1.8 λ, where λ is the wavelength of light used, in a Young’s double slit experiment is

Q. The maximum number of possible interference maxima for slit separation equal to 1.8 , where is the wavelength of light used, in a Young’s double slit experiment is

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Solution:

As and cannot be

or
Hence maximum number of possible
interference maximas,

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2. In Young's double slit experiment, how many maxima can be obtained on a screen (including central maxima), if (where is the wavelength of light)?

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4. Using monochromatic light of wavelength , an experimentalist sets up the Young's double slit experiment in three ways as shown.
If she observes that y = the wavelength of light used is :

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5. At two points P and Q on a screen in Young's double slit experiment, waves from slits and have a path difference of 0 and respectively. The ratio of intensities at P and Q will be :

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