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  4. The maximum number of possible interference maxima for slit separation equal to 1.8 λ, where λ is the wavelength of light used, in a Young’s double slit experiment is

Q. The maximum number of possible interference maxima for slit separation equal to 1.8 , where is the wavelength of light used, in a Young’s double slit experiment is

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Solution:

As and cannot be

or
Hence maximum number of possible
interference maximas,

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5. In a Young’s double slit experiment, one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If be the maximum intensity, the resultant intensity when they interfere at phase difference , is given by

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2. In Young's double slit experiment, how many maxima can be obtained on a screen (including central maxima), if (where is the wavelength of light)?

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3. Light of wavelength is incident normally on a slit of width . The angular width of central maxima in the diffraction pattern is (measured from minimum to minimum)

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4. Using monochromatic light of wavelength , an experimentalist sets up the Young's double slit experiment in three ways as shown.
If she observes that y = the wavelength of light used is :
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5. At two points P and Q on a screen in Young's double slit experiment, waves from slits and have a path difference of 0 and respectively. The ratio of intensities at P and Q will be :

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