Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be

Question

Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be (A) 2 (B) 3 (C) 5 (D) 6

Tardigrade Admin · Accepted Answer

Number of spectral lines in the emission spectrum when an electron jumps from state n to ground state is N = (n(n -1)/2) Here, n =4 ∴ : : N = (4(4 -1)/2) = 6

Q. Hydrogen atom is excited from ground state to another state with principal quantum number equal to $4$ . Then the number of spectral lines in the emission spectra will be

2

3

5

6

Number of spectral lines in the emission spectrum when an electron jumps from state $n$ to ground state is
$N = \frac{n ( n - 1 )}{2}$
Here, $n = 4$
$∴ N = \frac{4 ( 4 - 1 )}{2} = 6$

Q. Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be

2

3

5

6

Number of spectral lines in the emission spectrum when an electron jumps from state n to ground state is N=2n(n−1)​ Here, n=4 ∴N=24(4−1)​=6

Q. Hydrogen atom is excited from ground state to another state with principal quantum number equal to $4$ . Then the number of spectral lines in the emission spectra will be

Number of spectral lines in the emission spectrum when an electron jumps from state $n$ to ground state is
$N = \frac{n ( n - 1 )}{2}$
Here, $n = 4$
$∴ N = \frac{4 ( 4 - 1 )}{2} = 6$