Question

Critical angle for certain medium is $Si{n}^{-1}$ $(0.6)$. The polarizing angle of that medium is .......

• A. $Ta{n}^{-1}[1.6667]$
• B. $Ta{n}^{-1}[0.6667]$
• C. $Ta{n}^{-1}[1.5]$
• D. $Si{n}^{-1}[0.8]$

Answer 1

Answer: (A)

Critical angle, $C={\sin }^{-1}(0.6)$
$\sin (C)=0.6$
$\mu =\frac{1}{\sin C}=\frac{1}{0.6}$
Polarising angle $i_p={\tan }^{-1}(\mu )={\tan }^{-1}\left(\frac{1}{0.6}\right)$
$={\tan }^{-1}(1.6667)$