Q. The image of the point $(2,3)$ on the line $x+3 y+4=0$ is
Solution:
Using fact (short cut) the image of $(h, k)$ in the line $a x+b y+c=0$ is given by
$\frac{x-h}{a}=\frac{y-k}{b}=-\frac{2(a h+b k+c)}{a^{2}+b^{2}}$
$ \therefore \frac{x-2}{1}=\frac{y-3}{3}=-\frac{2(1)+3(3)+4}{10} $
$ x =-1, y =-6$
Questions from KCET 2022
Mathematics Most Viewed Questions
1. The solution of $\frac{dy}{dx} = \frac{y}{x}+\tan \frac{y}{x}$ is
WBJEE 2011
Differential Equations
2. The solution of the differential equation $\frac{dy}{dx} = (x +y)^2$ is
COMEDK 2009
Differential Equations
3. $\int\frac{1}{\sin x\, \cos x}$ dx is equal to
KEAM 2016
Integrals
4. If $\begin{bmatrix}1&- \tan\theta \\ \tan \theta&1\end{bmatrix}\begin{bmatrix}1&\tan \theta \\ - \tan \theta &1\end{bmatrix}^{-1} = \begin{bmatrix}a&-b\\ b&a\end{bmatrix}$ then
COMEDK 2009
Matrices
5. The value of $ \int{\frac{{{x}^{2}}+1}{{{x}^{4}}-{{x}^{2}}+1}}dx $ is
KEAM 2007
Integrals
Latest Updates
- JEE Main 2023 February 25th Shift 1 Morning
- JEE Main 2023 February 25th Shift 2 Evening
- JEE Main 2023 January 31st Shift 1 Morning
- JEE Main 2023 January 31st Shift 2 Evening
- JEE Main 2023 January 30th Shift 1 Morning
- JEE Main 2023 January 30th Shift 2 Evening
- JEE Main 2023 January 25th Shift 1 Morning
- JEE Main 2023 January 25th Shift 2 Evening
- JEE Main 2023 January 24th Shift 1 Morning
- JEE Main 2023 January 24th Shift 2 Evening
- JEE Main 2023 February 1st Shift 1 Morning
- JEE Main 2023 February 1st Shift 2 Evening
- JEE Main 2022 July 25th Shift 1 Morning
- JEE Main 2022 July 25th Shift 2 Evening
- JEE Main 2022 July 26th Shift 1 Morning
- JEE Main 2022 July 28th Shift 1 Morning
- JEE Advanced 2022 Paper 2
- JEE Advanced 2022 Paper 1
- JEE Advanced 2021 Paper 2
- JEE Advanced 2021 Paper 1
- JEE Advanced 2020 Paper 2
- JEE Advanced 2020 Paper 1
- NEET 2022 Physics Answer Key
- NEET 2022 Chemistry Answer Key
- NEET 2022 Botany Biology Answer Key
- NEET 2022 Zoology Biology Answer Key
- NEET Rank Predictor 2023