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  4. The combined equation of the diagonals of a parallelogram P Q R S is 6 x2+16 x y-6 y2-31 x+13 y+28=0. Then P Q R S must be

Q. The combined equation of the diagonals of a parallelogram $P Q R S$ is $6 x^{2}+16 x y-6 y^{2}-31 x+13 y+28=0$. Then $P Q R S$ must be

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Solution:

The lines represented by the given equation are perpendicular (here $a+b=0$ ).
$\therefore$ diagonals are perpendicular.

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