Q. The angle strain in cyclo pentane is :

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$24^{\circ} 44^{1}$

$29^{\circ} 16^{1}$

$9^{\circ} 44^{1}$

$0^{\circ} 44^{1}$

Solution:

Explanation: Angle strain $=1 / 2\left[109^{\circ} 28^{\prime}-108^{\circ}\right]=1^{\circ} 28^{\prime} / 2 $
$=0^{\circ} 88^{\prime} / 2 $
$=0^{\circ} 44^{\prime}$

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