Q. Propane- $1$ -ol can be prepared from propene by which of the following?

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A

$H_{2}O/H_{2}SO_{4}$

B

$Hg\left(\right.OAc\left(\left.\right)_{2} /H_{2}O$ followed by $NaBH_{4}$

C

$B_{2}H_{6}$ followed by $H_{2}O_{2}/OH^{-}$

D

$CH_{3}CO_{2}H/H_{2}SO_{4}$

Solution:

$Propan-1-ol$ an be prepared from propene as follows:
$\left(CH\right)_{2}CH=\left(CH\right)_{2}\overset{B_{2} H_{6}}{ \rightarrow }\left(\left(CH\right)_{2} \left(CH\right)_{2} \left(CH\right)_{2}\right)_{2}B\overset{H_{2} O_{2} / \left(OH\right)^{-}}{ \rightarrow }\left(CH\right)_{3}-\left(CH\right)_{2}-\left(CH\right)_{2}-OH \\ 1-\text{ propanol }$ $\text{CH}_{3}\text{CH}=\text{CH}_{2} \rightarrow _{\text{dilH}_{2} \text{SO}_{4}}^{HOH}\underset{\overset{\left|\right.}{2 - propanol}}{\text{CH}_{3} \text{CHCH}_{3}}$
(This addition follow Markownikoff's rule)

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