1. Tardigrade
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  3. Mathematics
  4. Let ax 3+ bx 2+ cx + d =|5 x x+1 x-1 x-3 -2 x x+2 x+3 x-4 5 x| where a , b , c are constants, then the value of d is

Q. Let $ax ^{3}+ bx ^{2}+ cx + d =\begin{vmatrix}5 x & x+1 & x-1 \\ x-3 & -2 x & x+2 \\ x+3 & x-4 & 5 x\end{vmatrix}$ where $a , b , c$ are constants, then the value of $d$ is

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Solution:

Put $x=0$ we get $d=\begin{vmatrix}0 & 1 & -1 \\ -3 & 0 & 2 \\ 3 & -4 & 0\end{vmatrix}$
$=-1(0-6)-1(12-0)=6-12=-6$

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