Q. In the system $X+2Y\rightleftharpoonsZ$ , the equilibrium concentrations are, $\left[\right.X\left]\right.=0.06molL^{- 1}$ , $\left[\right.Y\left]\right.=0.12molL^{- 1}$ , $\left[\right.Z\left]\right.=0.216molL^{- 1}$ . Find the equilibrium constant of the reaction.

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A

$250$

B

$500$

C

$125$

D

$273$

Solution:

$X+2Y\rightleftharpoonsZ$
$K_{C}=\frac{0 . 216}{0 . 06 \times \left(\right. 0 . 12 \left(\left.\right)^{2}}$
$K_{C}=250$

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