Q. If $\tan \left(\frac{p \pi}{4}\right)=\cot \left(\frac{q \pi}{4}\right)$ if then
Solution:
$\tan \left(\frac{ p \pi}{4}\right)=\cot \left(\frac{ q \pi}{4}\right) $
$\Rightarrow \tan \left(\frac{ p \pi}{4}\right)=\tan \left(\frac{\pi}{2}-\frac{ q \pi}{4}\right) $
$\Rightarrow \frac{ p \pi}{4}= n \pi+\frac{\pi}{2}-\frac{ q \pi}{4}$
$\Rightarrow p \pi=4 n \pi+2 \pi- q \pi$
$ \Rightarrow( p + q ) \pi=2(2 n +1) \pi $
$\Rightarrow p + q =2(2 n +1)$
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