Q. If $f(x)=e^{x}$ and $g(x)=\log x$ then the derivative of $f o g+g o f$ is

Solution:

$f og(x)+g \circ f(x)=e^{\log x}+\log \left(e^{x}\right)=x+x=2 x$
$\therefore$ the derivative of $f o g+g o f$ is $2$ .