Question

For Daniell cell,
$Zn\left(\right.s\left.\right)+Cu^{2 +}\left(\right.aq\left.\right)\rightleftharpoonsCu\left(\right.s\left.\right)+Zn^{2 +}\left(\right.aq\left.\right)$
The reaction quotient Q is given by
$Q=\frac{\left[\right. Z n^{2 +} \left]\right.}{\left[\right. C u^{2 +} \left]\right.}$

OA = 1.10 volt
Where $E_{c e l l}=1.1591$ volt, then

• A. Q = 0.01
• B. Q = 100
• C. Q = 0.1
• D. Q = 1

Answer 1

Answer: (A)

$E=E^\circ -\frac{0.059}{n}log_{10}Q$
For Daniell cell, $E^\circ =1.10$ V (equal to OA)
$E=1.10-\frac{0.059}{2}log0.01$
$=+1.159$ V