Q. Dissolving metallic $Zn$ in excess of $NaOH$ produces :-

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A

$Na_{2}ZnO_{2}$

B

$Zn\left(\right.OH\left(\left.\right)_{2}$

C

$ZnO$

D

$Zn\left(\right.OH\left(\left.\right)_{2}\&\left(Na\right)_{2}\left(ZnO\right)_{2}$

Solution:

$NaOH+Zn \rightarrow Na_{2}ZnO_{2}+H_{2}$

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