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  4. displaystyle lim n arrow ∞(3n+4n)(1/n)=

Q. $\displaystyle\lim _{n \rightarrow \infty}\left(3^{n}+4^{n}\right)^{\frac{1}{n}}=$

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Solution:

$\displaystyle\lim _{n \rightarrow \infty}\left(3^{n}+4^{n}\right)^{\frac{1}{n}}=\max \{3,4\}=4$

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