Q. Benzamide is obtained from:

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Benzaldehyde and hydroxyl amine

Benzaldehyde and ammonia

Salicyclic acid ammonia

Benzonic acid and ammonia

Solution:

Reaction: $\underset{\text{Benzoic acid}}{C_6H_5 .COOH} + \underset{\text{Ammonia}}{NH_3} \rightarrow C_6H_5COONH_4 \xrightarrow{\Delta} \underset{\text{Benzamide}}{C_6H_5CONH_2} + H_2O$

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$\frac{1}{2} O _{2}+2 H ^{+}+2 e ^{-} \rightarrow H _{2} O ,$
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$\lambda^{o}_{m}\left(K_{2}SO_{4}\right) = y S\,cm^{2} mol^{-1}$
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$\lambda^{o}_{m}\left(in \,S \,cm^{2} mol^{-1}\right)$ for $CH_3COOH$ will be-

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