Q. Acetaldehyde is obtained in the reactions:

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$CH _{2}= CH - CH _{2}- CH = CH _{2} \xrightarrow[2. Zn H _{2} O ]{1 . O _{3}}$

$HC \equiv CH + H _{2}^{\prime} O \xrightarrow{ HgSO _{4}}$

$CH _{3} COCl + H _{2} O \xrightarrow{ Pd -B a S O_{4}}$

Solution:

Correct answer is (a) Correct answer is (c) $HC \equiv CH + H _{2}^{\prime} O \xrightarrow{ HgSO _{4}}$Correct answer is (d) $CH _{3} COCl + H _{2} O \xrightarrow{ Pd -B a S O_{4}}$

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