Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The reduction of benzoyl chloride with H2/Pd BaSO4 gives
Q. The reduction of benzoyl chloride with
H
2
/
P
d
B
a
S
O
4
gives
3871
162
UP CPMT
UP CPMT 2010
Aldehydes Ketones and Carboxylic Acids
Report Error
A
benzoic acid
9%
B
toluene
10%
C
benzaldehyde
77%
D
benzyl alcohol
4%
Solution:
Reduction of benzoyl chloride with
H
2
/
P
d
in
B
a
S
O
4
forms benzaldehyde
This is known as Rosenmund reduction