Question

Which of the following statements is/are true?
(i) $PH_{5} \, $ and $BiCl_{5}$ do not exist
(ii) $p \, \pi -d \, \pi $ bond is present in $SO_{2}$
(iii) $I_{3}^{+}$ has bent geometry
(iv) $SeF_{4} \, and \, CH_{4}$ have same shape

• A. (i), (ii), (iii)
• B. (i), (iii)
• C. (i), (iii), (iv)
• D. (i), (ii), (iv)

Answer 1

Answer: (A)

(i) $\text{PH}_{5}$ does not exist because the electronegativity of H & P are almost same they should have $\text{sp}^{3} \text{d}$ hybridised but the H cannot distort the d orbital of P hence it is not exist while $\text{BiCl}_{5}$ $\text{Bi}^{+ 3}$ is more stable than $\text{Bi}^{+ 3}$ due to inert inert pair effect and in $\text{BiCl}_{5}$ steric crowding also present so it does not exist.
(ii) $\text{S} = 1 \text{s}^{2} 2 \text{s}^{2} 2 \text{p}^{6} 3 \text{s}^{2} 3 \text{p}^{4} 3 \text{d}^{0}$
In exicited state
p & d orbital of sulphur & p orbital of oxygen involved in $\text{\pi }$ bond so $\text{SO}_{2}$ has $\text{p\pi } - \text{d\pi }$ bond
(iii) $\text{I}_{3}^{+}$
$2b \text{p} + 2l \text{p} = \text{sp}^{3} \text{hybridisation}$
(iv) $\text{SeF}_{4} \, \& \, \text{CH}_{4}$