An alkene (.A.) on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane (.B.) . (.B.) is the lowest alkane which in pure form can not be prepared by standard Wurtz method. (.A.) is

Question

An alkene (.A.) on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane (.B.) . (.B.) is the lowest alkane which in pure form can not be prepared by standard Wurtz method. (.A.) is (A) MeCH=CHMe (B) MeCH2CH=CMe2 (C) MeCH2CH2CH2CH=CEt2 (D) MeCH2CH2CH=C(.Me.)Et

Tardigrade Admin · Accepted Answer

Simplest alkane which cannot be prepared by wurtz reaction is propane. So the alkene must be unsymmetrical having six carbon, which can give two different carbonyl each contain three carbons. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-xfhirnco7olmiose.jpg" />

Q. An alkene $(A)$ on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane $(B)$ . $(B)$ is the lowest alkane which in pure form can not be prepared by standard Wurtz method. $(A)$ is

$M e C H = C H M e$

$M e C H_{2} C H = CM e_{2}$

$M e C H_{2} C H_{2} C H_{2} C H = CE t_{2}$

$M e C H_{2} C H_{2} C H = C (M e) Et$

Simplest alkane which cannot be prepared by wurtz reaction is propane. So the alkene must be unsymmetrical having six carbon, which can give two different carbonyl each contain three carbons.

Q. An alkene (A) on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane (B) . (B) is the lowest alkane which in pure form can not be prepared by standard Wurtz method. (A) is

MeCH=CHMe

MeCH2​CH=CMe2​

MeCH2​CH2​CH2​CH=CEt2​