Q. What will be the degree of hydrolysis of 0.1 M solution of NaX? When a weak acid HX forms a salt NaX on reacting with NaOH and the dissociation constant of HX is 10^-5

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$0.01\%$ .

$0.1\%$ .

$0.001\%$ .

$0.15\%$ .

Solution:

$NaX+H_{2}O\rightleftharpoonsNaOH+H^{+}\times X^{-}$
$h=\sqrt{\frac{K_{w}}{K_{a} \times c} \, }=\sqrt{\frac{10^{- 14}}{10^{- 5} \times 10^{- 1}}}=\sqrt{10^{- 8}}$ .
$h=10^{- 4},$ percentage $h=10^{- 4}\times 100=0.01\%$ .

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