1. Tardigrade
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  3. Chemistry
  4. What mass of N2H4 can be oxidised to N2 by 24.0 g K2CrO4 , which is reduced to (C r (. O H .)4- (Given: Molar mass of textK text2 textCrO text4 text= text194 text.2 )

Q. What mass of $N_{2}H_{4}$ can be oxidised to $N_{2}$ by 24.0 g $K_{2}CrO_{4}$ , which is reduced to $\left(C r \left(\right. O H \left.\right)_{4}^{- \, \, }$ (Given: Molar mass of $\text{K}_{\text{2}} \text{CrO}_{\text{4}} \, \text{=} \, \text{194} \text{.2}$ )

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Solution:

$N_{2}^{2 -} \rightarrow N_{2}^{0}+ \, 4e$
$C r^{6 +} + \, 3 e \, \, \rightarrow C r^{3 +}$
Meq. of $N_{2}H_{4}$ = Meq. of $K_{2}C r O_{4}$
$\frac{w \, \, \, }{32 / 4}\times \, 1000 \, =\frac{24}{194.2 / 3}\times 1000$ $\left(E . \, w t \, = \frac{M \, w t .}{v a l e n c e \, f a c t o r} \, \right)$
$\text{w}_{\text{N}_{\text{2}} \text{H}_{\text{4}}} \text{= 2} \text{.97} \, \text{g}$

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