Q. Uncertainty in position and momentum are equal. Uncertainty in velocity is

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$\frac{h}{2 \pi }$

$\sqrt{\frac{h}{\pi }}$

$\frac{1}{2 m}\sqrt{\frac{h}{\pi }}$

None of these

Solution:

$\Delta p.\Delta x=\frac{h}{4 \pi }$
$\Delta p=\Delta x$ (Given)
$\left(\right.\Delta p\left(\left.\right)^{2}=\frac{h}{4 \pi }$
$\left(\right.m\Delta v\left(\left.\right)^{2}=\frac{h}{4 \pi }$
$\Delta v=\frac{1}{2 m}\sqrt{\frac{h}{\pi }}$

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