Q. Three equal weights of mass each are hanging on a string passing over a fixed pulley as shown in figure- The tension in the string connecting weight and is : (Take )

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Solution:


For ...(1)
B, 30+T_{2}-T_{1} =3 a\,\,\.(1),(2)30+30-3 a-30-3 a=3 a9 a=30a=\frac{10}{3} \,m / s ^{2}T_{2}=30-3\left(\frac{10}{3}\right)T_{2}=20 \,N =2 \,kgwt