Q. Consider the situation shown in the figure. The wall is smooth but the surfaces of blocks and in contact are rough. The friction on due to in equilibrium



Question

 2338  223 NTA AbhyasNTA Abhyas 2020Laws of Motion Report Error

Solution:

Solution

Block 'A' cannot be in equilibrium. Due to F sin θ component (upwards) on block 'B', Block 'A' moves downwards relative to block 'B'. So, friction on block 'B' downwords.