Q. Three equal weights of mass $3 kg$ each are hanging on a string passing over a fixed pulley as shown in figure-$2.147.$ The tension in the string connecting weight $B$ and $C$ is : (Take $g=10 \,m / s ^{2}$ )Physics Question Image

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Solution:

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For $A, T_{1}-30 =3 a \,\,\,$...(1)
$ \Rightarrow T_{1} =30+3 a
For $B, 30+T_{2}-T_{1} =3 a\,\,\.$...(2)
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From $(1),(2)$ and (3),
$30+30-3 a-30-3 a=3 a$
$9 a=30$
$a=\frac{10}{3} \,m / s ^{2}$
$T_{2}=30-3\left(\frac{10}{3}\right)$
$T_{2}=20 \,N =2 \,kgwt$