Q. The oxidation states of Cr in $\left[\right.Cr\left(\right.H_{2}O\left(\left.\right)_{6}\left]\right.Cl_{3},\left[\right.Cr\left(\right.C_{6}H_{6}\left(\left.\right)_{2}\left]\right.$ and $K_{2}\left[\right.Cr\left(\right.CN\left(\left.\right)_{2}\left(\right.O\left(\left.\right)_{2}\left(\right.O_{2}\left.\right)\left(\right.NH_{3}\left.\right)\left]\right.$ respectively are
Solution:
Compound
Oxidation state of Cr
$\left[\right.Cr\left(\right.H_{2}O\left(\left.\right)_{6}\left]\right.Cl_{3}$ +3
$\left[\right.Cr\left(\right.C_{6}H_{6}\left(\left.\right)_{2}\left]\right.$ 0
$K_{2}\left[\right.Cr\left(\right.CN\left(\left.\right)_{2}\left(\right.O\left(\left.\right)_{2}\left(\right.O_{2}\left.\right)\left(\right.NH_{3}\left.\right)\left]\right.$ +6
[Potassium amminedicyanodioxoperoxochromate (VI)]
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