Q. The oxidation state of molybdenum in its oxo complex species $\left[\right.Mo_{2}O_{4}\left(\right.C_{2}H_{4}\left(\left.\right)_{2}\left(\right.NH_{3}\left.\right)\left(\left]\right.\right)^{2 -}$ is

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Solution:

$\left[\right.Mo_{2}O_{4}\left(\right.C_{2}H_{4}\left(\left.\right)_{2}\left(\right.NH_{3}\left.\right)\left(\left]\right.\right)^{2 -}$
So $2x-8+0+0=-2$
$x=+3$ .

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