Q. The enthalpy of hydrogenation of cyclohexene is - 119.5 kJ mol-1. If resonance energy of benzene is -150.4 kJ mol-1, its enthalpy of hydrogenation would be
Solution:
Enthalpy of hydrogenation of benzene
$= 3 Δ \left(\text{H}\right)_{\text{Hydrogenation}} - \left(\text{R.E}\right)$
$= 3 \times \left(- 1 1 9 · 5\right) - \left(- 1 5 0 · 4\right) = - 3 5 8 · 5 + 1 5 0 · 4$
$= - 2 0 8 · 1 \text{ kJ mol}^{- 1}$
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