Q. The compound formed in the positive test for nitrogen with the lassaigne solution of an organic compounds is

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A

$Fe\left(\right.CN\left(\left.\right)_{3}$

B

$\left(Na\right)_{3}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left]\right.$

C

$\left(Fe\right)_{4}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left(\left]\right.\right)_{3}$

D

$\left(Na\right)_{4}\left[\right.Fe\left(\right.CN\left(\left.\right)_{5}NOS\left]\right.$

Solution:

$\left(Fe\right)_{4}\left[\right.Fe\left(\right.CN\left(\left.\right)_{6}\left(\left]\right.\right)_{3}$ compound formed in the positive test for nitrogen with the lassaigne solution of an organic compounds.

Questions from NTA Abhyas 2022

1. An alkene $\left(\right.A\left.\right)$ on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane $\left(\right.B\left.\right)$ . $\left(\right.B\left.\right)$ is the lowest alkane which in pure form can not be prepared by standard Wurtz method. $\left(\right.A\left.\right)$ is

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4. At standard conditions, if the change in the enthalpy for the following reaction is $-109 \,kJ\, mol^{-1}$ $H_{2(g)}+Br_{2(g)} \to 2HBr_{(g)}$ Given that bond energy of $H_{2}$ and $Br_{2}$ is $435\,KJ\,mol^{-1}$ and $192\,KJ\,mol^{-1}$ , respectively, what is the bond energy (in $KJ \,mol^{-1})$ of $HBr$ ?

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5. The density of 2 M aqueous solution of NaOH is 1.28 g/cm$^3$. The molality of the solution is
[Given that molecular mass of NaOH = 40 g mol$^{-1}$]

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