Q. Pick out the correct statement with respect to $\left[\right.Mn\left(\right.CN\left(\left.\right)_{6}\left(\left]\right.\right)^{3 -}$

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It is $sp^{3}d^{2}$ hybridised and tetrahedral

It is $d^{2}sp^{3}$ hybridised and octahedral

It is $dsp^{2}$ hybridised and square planar

It is $sp^{3}d^{2}$ hybridised and octahedral

Solution:

As in $\left[\right.Mn\left(\right.CN\left(\left.\right)_{6}\left(\left]\right.\right)^{3 -}$ Coordination number is 6 and $\text{CN}^{-}$ being strong ligand paired up inner 3d $e^{-}$ so it is $d^{2}sp^{3}$ and octahedral complex.

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