Q. In the reaction, $H_{3}PO_{4}+Ca\left(\right.OH\left(\left.\right)_{2} \rightarrow CaHPO_{4}+2H_{2}O,$ the equivalent mass of $H_{3}PO_{4}$ is

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A

32.7 g

B

49 g

C

196 g

D

98 g

Solution:

In the reaction
$H_{3}PO_{4}+Ca\left(\right.OH\left(\left.\right)_{2} \rightarrow CaHPO_{4}+2H_{2}O,$
Basicity of phosphoric acid is 3.
Thus, equivalent mass of $H_{3}PO_{4}=\frac{M o l e c u l a r m a s s}{B a s i c i t y}$
$=\frac{98}{3}=32.7g$ .

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