Q. In the following sequence of reaction,
$\text{CH}_{3} \text{CH}_{2} \text{CH}_{2} \text{CH}_{2} \text{Br} \overset{\text{alc. KOH}}{ \rightarrow } A \overset{\text{HBr}}{ \rightarrow } B \overset{\text{aq. KOH}}{ \rightarrow } C$ ,
The product $'C'$ is $?$

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A

$Butan-2-ol$

B

$Butan-1-ol$

C

Butyne

D

Butene

Solution:

$\text{C} \left(\text{H}\right)_{3} \text{C} \left(\text{H}\right)_{2} \text{C} \left(\text{H}\right)_{2} \text{C} \left(\text{H}\right)_{2} \text{B} \text{r} & \overset{\text{a} \text{l} \text{c} . \, \text{K} \text{O} \text{H}}{ \rightarrow } & \text{C} \left(\text{H}\right)_{3} - \text{C} \left(\text{H}\right)_{2} - \text{C} \text{H} = \text{C} \left(\text{H}\right)_{2} + \text{H} \text{B} \text{r} \overset{\text{H} \text{B} \text{r}}{ \rightarrow } & \text{C} \left(\text{H}\right)_{3} \text{C} \left(\text{H}\right)_{2} \underset{\overset{\left|\right.}{\text{B} \text{r}}}{\text{C} \text{H}} - \text{C} \left(\text{H}\right)_{3} & \overset{\text{aq} \text{. KOH}}{ \rightarrow } & \text{C} \left(\text{H}\right)_{3} - \text{C} \left(\text{H}\right)_{2} - \underset{\overset{\left|\right.}{\text{OH}}}{\text{C} \text{H}} - \text{C} \left(\text{H}\right)_{3} \\ & & \left(\right. \text{A} \left.\right) & \left(\right. \text{B} \left.\right) & & \left(\right. \text{C} \left.\right)$

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