Q. Arrange the following compounds in order of their reactivity towards $S_{N}2$ reaction
$\left(\right.i\left.\right)$ $CH_{3}\left(\right.CH_{2}\left(\left.\right)_{3}CH_{2}Br$
$\left(\right.ii\left.\right)$ $\left(\right.CH_{3}\left(\left.\right)_{2}CHCH_{2}CH_{2}Br$
$ \, \, \, \left(\text{CH}\right)_{\text{3}} \\ \, \text{|} \\ \left(\text{iii}\right) \, \left(\text{CH}\right)_{\text{3}}\left(\text{CH}\right)_{\text{2}}-\text{CH}-\left(\text{CH}\right)_{\text{2}}\text{Br}$
$ \, \, \, \left(\text{CH}\right)_{\text{3}} \\ \, \text{|} \\ \left(\text{iv}\right) \, \left(\text{CH}\right)_{\text{3}}-\text{C}-\left(\text{CH}\right)_{\text{2}}\text{Br} \\ \, \text{|} \\ \, \, \, \left(\text{CH}\right)_{\text{3}}$

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Solution:

Order of reactivity of alkyl halides towards $S_{N}2$ reaction is $1^\circ >2^\circ >3^\circ $ . Here the reactivity order is as follows
Solution