Q. A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be?

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0.59 V

0.118 V

1.18 V

0.059 V

Solution:

$H_{2} \rightarrow 2H^{+}+2e^{-}$
$E_{o x i l}=E_{o x i d}^{0}-\frac{0.059}{2}log_{10}\frac{\left(\right. H^{+} \left(\left.\right)^{2}}{P_{H_{2}}}$
$=0-\frac{0.059}{2}log_{10}\frac{\left(\right. 1 0^{- 10} \left(\left.\right)^{2}}{1}=0.59V$

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